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	<title>Comments on: How do you calculate the mass of silver chloride in this chemistry problem?</title>
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	<pubDate>Tue, 22 May 2012 11:14:34 +0000</pubDate>
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		<title>By: Steve O</title>
		<link>http://www.thefoolsgold.net/silver/how-do-you-calculate-the-mass-of-silver-chloride-in-this-chemistry-problem/comment-page-1#comment-7518</link>
		<dc:creator>Steve O</dc:creator>
		<pubDate>Thu, 28 Jan 2010 11:44:59 +0000</pubDate>
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		<description>use molar masses:
0.165 grams Ag @  (143.32 g/mol AgCl) / (107.9 g/mol Ag) = 
0.219  g AgCl would be required

or 

using a ratio of  % 's
0.165 g Ag  @ (100 % AgCl) / (75.27% Ag) =
0.219 g of AgCl would be required


in both ways, 
your answer is 
219 mg of AgCl&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;</description>
		<content:encoded><![CDATA[<p>use molar masses:<br />
0.165 grams Ag @  (143.32 g/mol AgCl) / (107.9 g/mol Ag) =<br />
0.219  g AgCl would be required</p>
<p>or </p>
<p>using a ratio of  % &#8217;s<br />
0.165 g Ag  @ (100 % AgCl) / (75.27% Ag) =<br />
0.219 g of AgCl would be required</p>
<p>in both ways,<br />
your answer is<br />
219 mg of AgCl<br /><b>References : </b></p>
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