The Fools Gold

Silver chloride, often used in silver plating, contains 75.27% Ag.

Calculate the mass of silver chloride required to plate 165 mg of pure silver?

use molar masses:
0.165 grams Ag @ (143.32 g/mol AgCl) / (107.9 g/mol Ag) =
0.219 g AgCl would be required

or

using a ratio of % ’s
0.165 g Ag @ (100 % AgCl) / (75.27% Ag) =
0.219 g of AgCl would be required

in both ways,
your answer is
219 mg of AgCl

One Response

1. Steve O Says:
   January 28th, 2010 at 6:44 am

   use molar masses:
   0.165 grams Ag @ (143.32 g/mol AgCl) / (107.9 g/mol Ag) =
   0.219 g AgCl would be required

   or

   using a ratio of % ’s
   0.165 g Ag @ (100 % AgCl) / (75.27% Ag) =
   0.219 g of AgCl would be required

   in both ways,
   your answer is
   219 mg of AgCl
   References :

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