How many grams of both silver nitrate and sodium nitrate are present after the reaction is complete?
Posted on February 17th, 2010 by admin
Solutions of sodium carbonate and silver nitrate react to form solid silver carbonate and a solution of sodium nitrate. A solution containing 3.20 g of sodium carbonate is mixed with one containing 4.57 of silver nitrate.
1- How many grams of silver nitrate are present after the reaction is complete?
2- How many grams of sodium nitrate are present after the reaction is complete?
Na2CO3 + 2 AgNO3 = Ag2CO3 + 2 NaNO3
moles Na2CO3 = 3.20 g / 105.988 g/mol= 0.0302
moles AgNO3 = 4.57 g / 169.87 g/mol=0.0269 => Limiting reactant
moles Na2CO3 required = 0.0269/2 =0.0135
moles Na2CO3 in excess = 0.0302 - 0.0135 = 0.0167
mass Na2CO3 in excess = 0.0167 x 105.988 = 1.77 g
AgNO3 is not present after the reaction is complete